MHT CET questions
29293 published questions with worked solutions.
- The value of _ x 0 e^ ax - e^ bx x is equal to
- _ x 0 e^ 5x - e^ 4x x is equal to
- _ x 0 a^x - b^x e^x - 1 is equal to
- _ x 0 [ 4x + 1 1 - 4x ]^ 1 x is equal to
- Find the value of _ x ax^2 + bx + c dx^2 + ex + f
- _ x ( x^3 3x^2 - 4 - x^2 3x + 2 ) is equal to
- _ x 2x - 1 x^2 + 2x + 1 is equal to
- _ x [ x^2 + 2x - 1 - x ] is equal to
- If 0 < a < b, then _ n a^n + b^n a^n - b^n is equal to
- _ x x^2 + 1 - [3] x^3 + 1 [4] x^4 + 1 - [5] x^4 + 1 equals
- _ x 4 |x - 4| x - 4 is equal to
- Find _ x 0 f(x) and _ x 1 f(x), where f(x) = cases 2x + 3, & x 0 3(x + 1), & x > 0 cases
- If f(x) = cases mx^2 + n, & x < 0 nx + m, & 0 x 1 nx^3 + m, & x > 1 cases , then
- Suppose f(x) = cases a + bx, & x < 1 4, & x = 1 b - ax, & x > 1 cases and if _ x 1 f(x) = f(1), then
- If f(x) = cases |x| + 1, & x < 0 0, & x = 0 |x| - 1, & x > 0 cases , then _ x a f(x) exists for all
- Let f(x) = cases x + 2, & x -1 cx^2, & x > -1 cases If _ x -1 f(x) exists, then c is equal to
- _ x 0 | x| x is
- If f(x) = cases x - |x| x , & x 0 2, & x = 0 cases , then _ x 0 f(x) is
- Let f(x) = cases x, & x > 0 x + k, & x < 0 cases The value of k, if _ x 0 f(x) exists, is
- _ x 2^- x [x] is equal to