MHT CET questions
29293 published questions with worked solutions.
- Find the value k, so that f(x) is continuous at x = 2: f(x) = cases kx - 1, & when x < 2 x + 1, & when x > 2 3, & when x = 2 cases
- If f(x) = cases (1 + 2x)^ 1/x , & for x 0 k, & for x = 0 cases , then
- f(x) = cases x^2 - 4 x - 2 + a, & for x < 2 8, & for x = 2 x + b + 4, & for x > 2 cases is continuous at x = 2, then the value of...
- If function f(x) = cases ax + 1, & x 2 x + b, & x > 2 cases is continuous, then
- The function f(x) = |3x - 4| 3x - 4 is discontinuous at
- If f(x) = cases -x, & if x 0 x, & if 0 < x 1 2 - x, & if 1 < x 2 1, & if x > 2 cases then f is discontinuous at x =
- If f(y) = (e^ 2y - 1) y y^2 , for y 0, = 4, for y = 0, then f(y) is
- f(x) = cases x, & 0 x < 1 2 1, & x = 1 2 1 - x, & 1 2 < x < 1 cases is
- f(x) = cases x^2 - x - 6 x - 3 , & if x 3 7, & if x = 3 cases is discontinuous at
- f(x) = x^2 + x - 2 x^2 - 3x + 2 is discontinuous at x =
- If f(x) = cases 5 2 - x, & when x < 2 1, & when x = 2 x - 3 2 , & when x > 2 cases , then
- In the following, discontinuous function is
- If f(x) = cases e^ 1 x , & when x 0 0, & when x = 0 cases , then
- If f(x) = cases 1 + x^2, & when 0 x 1 1 - x, & when x > 1 cases , then
- If f(x) = cases x^2, & when x 1 2, & when x = 1 cases , then
- If f(y) = y^2 - y - 1; for 0 y < 2 = 4y + 1; for 2 y 4, then f(y) is
- If f(x) = cases x - 1, & x < 0 1 4 , & x = 0 x^2, & x > 0 cases , then
- If f(x) = cases 1 x , & x 0 0, & x = 0 cases , then
- The following f is defined in (-2, 2) by f(x) = cases x + a, & if x < 0 x, & if 0 x < 1 b - x, & if x 1 cases If f is continuous...
- If function f(x) = cases 5x - 4, & 0 < x 1 4x^2 + 3bx, & 1 < x < 2 cases is continuous at every point of its domain, then b is...