JEE Advanced 2008 Mathematics question
Consider three planes
: x - y + z = 1, : x + y - z = -1, : x - 3y + 3z = 2.
Let be the lines of intersection of the planes and , and , and and , respectively.
STATEMENT-1: At least two of the lines and are non-parallel.
STATEMENT-2: The three planes do not have a common point.
Answer: (D)
Solution
All three normals cross-product directions are parallel to , so , making Statement-1 false.
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