JEE Main 2013 Physics question

Let [ε₀] denote the dimensional formula of the permittivity of vacuum. If M = mass, L = length, T = time and A = electric current, then -

• (1)[ε₀] = [M⁻¹ L² T⁻¹ A⁻²]
• (2)[ε₀] = [M⁻¹ L² T⁻¹ A]
• (3)[ε₀] = [M⁻¹ L⁻³ T² A]
• (4)[ε₀] = [M⁻¹ L⁻³ T⁴ A²]Correct