JEE Main 2013 Chemistry question
A gaseous hydrocarbon gives upon combustion 0.72 g. of water and 3.08 g. of CO₂. The empirical formula of the hydrocarbon is -
Answer: (2)
Solution
mol H₂O = 0.04 (0.08 mol H); mol CO₂ = 0.07 (0.07 mol C). Ratio C:H = 7:8, giving C₇H₈.