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JEE Main 2013 Chemistry question

ChemistryChemical KineticsJEE Main 2013

The rate of a reaction doubles when its temperature changes from 300 K to 310 K. Activation energy of such a reaction will be : (R = 8.314 JK⁻¹ mol⁻¹ and log 2 = 0.301)

Answer: (3)

Solution

Using Arrhenius equation, $(2) = Missing argument for \dfrac\dfrac{E_a}{2.303×8.314×10

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Question ID VK-000893