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JEE Main 2026 Physics question

PhysicsAtomsJEE Main 2026

If an alpha particle with energy 7.7 MeV is bombarded on a thin gold foil, the closest distance from nucleus it can reach is m. (Atomic number of gold = 79 and in SI units)

Answer: (1)

Solution

From energy conservation $Missing argument for \frac\frac{9× × 2 × 79 ×

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Question ID VK-000958