JEE Main 2026 Chemistry question

A hydrocarbon 'P' () on reaction with HCl gives an optically active compound 'Q' () which on reaction with one mole of ammonia gives compound 'R' (). 'R' on diazotization followed by hydrolysis gives 'S'. Identify P, Q, R and S.

• (1)P \Rightarrow CH_3-CH_2-CH=CH_2; Q \Rightarrow CH_3-CH_2-CH_2-CH_2Cl; R \Rightarrow CH_3-CH_2-CH_2-NHCH_3; S \Rightarrow CH_3-CH_2-CH(OH)CH_3
• (2)-cyclopropyl, -cyclopropyl, -cyclopropyl; cyclopropanol
• (3)P \Rightarrow CH_3-CH=CH-CH_3; Q \Rightarrow CH_3-CH_2-CHCl-CH_3; R \Rightarrow CH_3-CH_2-CH(NH_2)-CH_3; S \Rightarrow CH_3-CH_2-CH(OH)-CH_3Correct
• (4)P \Rightarrow CH_3-CH=CH-CH_3; Q \Rightarrow CH_3-CH_2-CH_2-CH_2-Cl; R \Rightarrow CH_3-CH_2-CH_2-CH_2-NH_2; S \Rightarrow CH_3-CH_2-CH_2-CH_2-OH