JEE Main 2026 Chemistry question

ChemistrySolutionsJEE Main 2026

A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is . (Nearest integer) [Given: of the solvent = 5.0 K kg mol] Assume the solution to be dilute and no association or dissociation of X takes place in solution.

Answer: 3

Solution

; using mole fraction of solute, relative lowering .

Question ID VK-001068