JEE Main 2026 Chemistry question
Dissociation of a gas takes place according to the following chemical reaction. At equilibrium, the total pressure is 1 bar at 300 K. The standard Gibbs energy of formation of the involved substances has been provided below:
Substance | /kJmol | -100.00 | -50.832
The degree of dissociation of is given by where x = . (Nearest integer). [Given: R = 8 J molK, log 2 = 0.3010, log 3 = 0.48]
Answer: 33
Solution
kJ. \lnK_p\lnK_p$ = 0.693 ⇒
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