JEE Main 2026 Chemistry question
If the enthalpy of sublimation of Li is 155 kJ mol⁻¹, enthalpy of dissociation of is 150 kJ mol⁻¹, ionization enthalpy of Li is 520 kJ mol⁻¹, electron gain enthalpy of F is -313 kJ mol⁻¹, standard enthalpy of formation of LiF is -594 kJ mol⁻¹. The magnitude of lattice enthalpy of LiF is kJ mol⁻¹ (Nearest integer).
Answer: 1031
Solution
Using Born-Haber cycle: , giving L.E. = -1031 kJ/mol.