JEE Main 2026 Physics question
One mole of an ideal diatomic gas expands from volume to isothermally at a temperature and does joule of work. If the gas undergoes same magnitude of expansion adiabatically from doing the same amount of work , then its final temperature will be (close to) .
Answer: 2
Solution
For Isothermal process
= nRT()
= 1 · R · 300 · (2)
= 300R(0.693)....(1)
Now for adiabatic process,
It is given work done in Isothermal = work
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