Let the circle x^2+y^2=4 intersect x-axis at the points A(a,0), a0 and B(b,0). Let P(2 , 2 ), 0

Question

Let the circle x^2+y^2=4 intersect x-axis at the points A(a,0), a>0 and B(b,0). Let P(2 , 2 ), 0< < 2 and Q(2 ,2 ) be two points such that ( - )= 2 . Then the point of intersection of AQ and BP lies on :

Accepted Answer

(1)

JEE Main 2026 Mathematics question

Solution

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