JEE Main 2026 Physics question
A particle starts moving from time t = 0 and its coordinate is given as x(t) = 4t³– 3t.. A. The particle returns to its original position (origin) 0.866 units later B. The particle is 1 unit away from origin at its turning point. C. Acceleration of the particle is non-negative. D. The particle is 0.5 units away from origin at its turning point. E. Particle never turns back as acceleration is non-negative. Choose the correct answer from the options given below:
Answer: (2)
Solution
at (0.866). at , giving (1 unit
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