JEE Main 2026 Physics question
The time period of a simple harmonic oscillator is . The measured value of mass (m) of the object is 10 g with an accuracy of 10 mg, and time for 50 oscillations of the spring is found to be 60 s using a watch of 2 s resolution. Percentage error in determination of spring constant(k) is %.
Answer: (4)
Solution
. With s, :
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