JEE Main 2025 Mathematics question
Using the principal values of the inverse trigonometric functions the sum of the maximum and the minimum values of 16((sec–1x)² + (cosec–1x)²) is :
Answer: (4)
Solution
Let sec⁻¹x = a, cosec⁻¹x = π/2 - a. Max at a=π gives 20π², min at a=π/4 gives 2π². Sum = 22π².