JEE Main 2025 Mathematics question
Let for ƒ(x) = 7tan⁸x + 7tan⁶x – 3tan⁴x – 3tan²x, and . Then 7I1 + 12I2 is equal to :
Answer: (3)
Solution
I1=0 by substitution tanx=t. I2 = 1/12 via integration by parts. 7(0)+12(1/12)=1.
Let for ƒ(x) = 7tan⁸x + 7tan⁶x – 3tan⁴x – 3tan²x, and . Then 7I1 + 12I2 is equal to :
I1=0 by substitution tanx=t. I2 = 1/12 via integration by parts. 7(0)+12(1/12)=1.