JEE Main 2025 Mathematics question
Let A be a square matrix of order 3 such that det(A) = –2 and det(3adj(–6adj(3A))) = , m > n. Then 4m + 2n is equal to .
Answer: 34
Solution
Computing det(3adj(-6adj(3A))) = 3²¹×2¹⁰. So m+n=10, mn=21, giving m=7, n=3. 4(7)+2(3)=34.