JEE Main 2025 Mathematics question
Let L1 : and L2 : , α ∈R, be two lines, which intersect at the point B. If P is the foot of perpendicular from the point A(1, 1, –1) on L2, then the value of 26 α(PB)² is .
Answer: 216
Solution
Solving for intersection gives B(4,0,-1), α=3. Foot of perpendicular P(40/13,0,-31/13). 26×3×(PB)² = 216.