JEE Main 2025 Physics question
Two soap bubbles of radius 2 cm and 4 cm, respectively, are in contact with each other. The radius of curvature of the common surface, in cm, is .
Answer: 4
Solution
r = (r1×r2)/(r2-r1) = (2×4)/(4-2) = 4 cm.
Two soap bubbles of radius 2 cm and 4 cm, respectively, are in contact with each other. The radius of curvature of the common surface, in cm, is .
r = (r1×r2)/(r2-r1) = (2×4)/(4-2) = 4 cm.