JEE Main 2025 Physics question
The position vectors of two 1 kg particles, (A) and (B), are given by m and m, respectively (α1 = 1 m/s², α2 = 3n m/s, α3 = 2 m/s, β1 = 2 m/s, β2 = –1 m/s², β3 = 4p m/s), where t is time, n and p are constants, At t = 1s, and velocities and of the particles are orthogonal to each other. At t = 1 s, the magnitude of angular momentum of particle (A) with respect to the position of particle (B) is kgm²s⁻¹. The value of L is .
Answer: 90
Solution
Solving orthogonality and magnitude conditions gives n=1/3, p=-1/4. Computing L = × gives magnitude √90, so L=90.