JEE Main 2025 Chemistry question
Niobium (Nb) and ruthenium (Ru) have "x" and "y" number of electrons in their respective 4d orbitals. The value of x + y is
Answer: 11
Solution
Nb: [Kr]4d5s, x=4. Ru: [Kr]4d5s, y=7. x+y=11.
Niobium (Nb) and ruthenium (Ru) have "x" and "y" number of electrons in their respective 4d orbitals. The value of x + y is
Nb: [Kr]4d5s, x=4. Ru: [Kr]4d5s, y=7. x+y=11.