JEE Main 2025 Chemistry question
Xg of benzoic acid on reaction with aq. release that occupied 11.2 L volume at STP. X is g.
Answer: 61
Solution
Moles of CO = 11.2/22.4 = 0.5 = moles of benzoic acid. Mass = 0.5 × 122 = 61 g.
Xg of benzoic acid on reaction with aq. release that occupied 11.2 L volume at STP. X is g.
Moles of CO = 11.2/22.4 = 0.5 = moles of benzoic acid. Mass = 0.5 × 122 = 61 g.