JEE Main 2025 Mathematics question
The number of different 5 digit numbers greater than 50000 that can be formed using the digits 0, 1, 2, 3, 4, 5, 6, 7, such that the sum of their first and last digits should not be more than 8, is
Answer: (4)
Solution
Cases give total 9×(8×8×8) = 4608 but 50000 is not included, so total numbers 4608 – 1 = 4607