JEE Main 2025 Chemistry question
The molarity of a 70% (mass/mass) aqueous solution of a monobasic acid (X) is × M(Nearest integer) [Given : Density of aqueous solution of (X) is 1.25 g Molar mass of the acid is 70 g ]
Answer: 125
Solution
In 100g solution, volume = 100/1.25 mL. Molarity = (70/70)/(100/1.25) × 1000 = 12.5 M = 125×10⁻¹