JEE Main 2025 Mathematics question
Let f : R → R be a twice differentiable function such that f(2) = 1. If F(x) = xf(x) for all x ∈ R, and , then is equal to
Answer: (1)
Solution
∫xF'(x)dx=6 gives ∫F(x)dx=–2. Second integral gives F'(2)=13. So F'(2)+∫F(x)dx = 13–2=11