JEE Main 2025 Physics question
A uniform magnetic field of 0.4 T acts perpendicular to a circular copper disc 20 cm in radius. The disc is having a uniform angular velocity of 10π rad s⁻¹ about an axis through its centre and perpendicular to the disc. What is the potential difference developed between the axis of the disc and the rim ? (π = 3.14)
Answer: (3)
Solution
E = (1/2)BωR² = 0.2512 V