JEE Main 2025 Physics question
The kinetic energy of translation of the molecules in 50g of CO2 gas at 17°C is:
Answer: (2)
Solution
KE = (3/2)KT × (50/44)×6.023×10²³ ≈ 4108.6 J (closest option 4102.8 J)
The kinetic energy of translation of the molecules in 50g of CO2 gas at 17°C is:
KE = (3/2)KT × (50/44)×6.023×10²³ ≈ 4108.6 J (closest option 4102.8 J)