JEE Main 2025 Mathematics question
Let A(4, –2), B(1, 1) and C(9, –3) be the vertices of a triangle ABC. Then the maximum area of the parallelogram AFDE, formed with vertices D, E and F on the sides BC, CA and AB of the triangle ABC respectively, is.
Answer: 3
Solution
Area of triangle ABC = 6; maximum area of such parallelogram is half the triangle's area = 3.