JEE Main 2025 Physics question
Energy released when two deuterons () fuse to form a helium nucleus () is (Given: Binding energy per nucleon of = 1.1 MeV and binding energy per nucleon of = 7.0 MeV)
Answer: (1)
Solution
Q = (4×7 - 4×1.1) MeV = 23.6 MeV