JEE Main 2025 Mathematics question
Not in JEE Main syllabus
If θ ∈ [–2π, 2π], then the number of solutions of , is equal to :
Answer: (3)
Solution
Factors to (2cosθ–√3)(√2cosθ+1)=0, giving cosθ=√3/2 or –1/√2, yielding 8 solutions in the given range.