JEE Main 2025 Chemistry question
Consider the following electrochemical cell at standard condition. Au(s)|QH₂,Q|NH₄X(0.01 M)||Ag⁺(1 M)|Ag(s) Ecell = + 0.4 V The couple QH₂/Q represents quinhydrone electrode, the half cell reaction is given below : The pKb value of the ammonium halide salt (NH₄X) used here is . (nearest integer)
Answer: 6
Solution
E°cell = 0.8-0.7=0.1V. 0.4=0.1-0.06log[H+], pH=5. pKb+log0.01=4, pKb=6.