JEE Main 2025 Chemistry question
Fortification of food with iron is done using FeSO4.7H2O. The mass in grams of the FeSO4.7H2O required to achieve 12 ppm of iron in 150 kg of wheat is (Nearest integer) [Given : Molar mass of Fe, S and O respectively are 56, 32 and 16 g mol⁻¹]
Answer: 9
Solution
ppm = (mass Fe/mass wheat)×10⁶. Solving gives mass of Fe=1.8g, then mass of FeSO4.7H2O = 278×1.8/56 ≈ 9 grams