JEE Main 2025 Mathematics question
Let the function f(x) = , x 0 be strictly increasing in and strictly decreasing in . Then is equal to
Answer: (3)
Solution
f'(x) = (x-3)(x+3)/. f'(x)>0 for x in (-∞,-3)∪(3,∞), f'(x)<0 for (-3,0)∪(0,3).
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