JEE Main 2025 Mathematics question
The number of integral terms in the expansion of is
Answer: (2)
Solution
requires r/8 and (1016-r)/2 to be integers, giving r = 0,8,16,...,1016, i.e., r=8k for k=0 to 127. Total 128 terms.
The number of integral terms in the expansion of is
requires r/8 and (1016-r)/2 to be integers, giving r = 0,8,16,...,1016, i.e., r=8k for k=0 to 127. Total 128 terms.