JEE Main 2025 Chemistry question
The number of species from the following that are involved in hybridization is [Co(NH)], SF, [CrF], [Mn(CN)] and [MnCl]
Answer: (4)
Solution
[Co(NH3)6]3+ is d²sp³ (low spin). SF6 is sp³d². [CrF6]3- is d²sp³. [Mn(CN)6]3- is d²sp³. [MnCl6]3- is sp³d². So sp³d² count =
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