JEE Main 2025 Chemistry question
Consider the following half cell reaction
(aq) + 6e + 14H (aq) 2Cr (aq) + 7HO()
The reaction was conducted with the ratio of = . The pH value at which the EMF of the half cell will become zero is . (nearest integer value)
[Given : standard half cell reduction potential = 1.33V, = 0.059V]
Answer: 10
Solution
Using Nernst equation: . Solving gives pH ≈ 10.10 ≈ 10.