JEE Main 2025 Chemistry question

ChemistryEquilibriumJEE Main 2025

The equilibrium constant for decomposition of ( = 92.34 kJ mol) is 8.0 × at 2300 K and total pressure at equilibrium is 1 bar. Under this condition, the degree of dissociation () of water is × (nearest integer value)

[Assume is negligible with respect to 1]

Answer: 5

Solution

. Solving gives .

Question ID VK-002864