JEE Main 2025 Chemistry question
The equilibrium constant for decomposition of ( = 92.34 kJ mol) is 8.0 × at 2300 K and total pressure at equilibrium is 1 bar. Under this condition, the degree of dissociation () of water is × (nearest integer value)
[Assume is negligible with respect to 1]
Answer: 5
Solution
. Solving gives .