JEE Main 2025 Physics question

PhysicsWave OpticsJEE Main 2025

In a Young's double slit experiment, two slits are located 1.5 mm apart. The distance of screen from slits is 2 m and the wavelength of the source is 400 nm. If the 20 maxima of the double slit pattern are contained within the central maximum of the single slit diffraction pattern, then the width of each slit is cm, where x-value is .

Answer: 15

Solution

mm cm.

Question ID VK-002992