JEE Main 2025 Chemistry question
Sea water, which can be considered as a 6 molar (6 M) solution of NaCl, has a density of 2 g mL. The concentration of dissolved oxygen () in sea water is 5.8 ppm. Then the concentration of dissolved oxygen () in sea water, is x × 10 m. x = . (Nearest integer) Given: Molar mass of NaCl is 58.5 g mol, Molar mass of = is 32 g mol
Answer: 2
Solution
5.8 ppm means 5.8×10⁻³ g O2 per 1 L seawater. Moles of O2 = 5.8×10⁻³/32.
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