JEE Main 2025 Physics question
An inductor of reactance 100 Ω, a capacitor of reactance 50 Ω, and a resistor of resistance 50 Ω are connected in series with an AC source of 10 V, 50 Hz. Average power dissipated by the circuit is W.
Answer: 1
Solution
Z=50√2Ω, cosφ=R/Z=1/√2. P=(I₀V₀/2)cosφ=1W.