JEE Main 2025 Chemistry question
Butane reacts with oxygen to produce carbon dioxide and water following the equation given below. If 174.0 kg of butane is mixed with 320.0 kg of O₂, the volume of water formed in liters is . (Nearest integer) [Given : (a) Molar mass of C, H, O are 12, 1, 16g mol⁻¹ respectively, (b) Density of water = 1 g mL⁻¹]
Answer: 138
Solution
Moles of C4H10 = 3×10³, moles of O2=10×10³. O2 is limiting; moles H2O formed = (10/13)×5×2×10³. Volume = (10/13)×5×2×18 ≈ 138.46 L.