JEE Main 2016 Physics question
A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1m 1000 times. Assume that the potential energy lost each time he lowers the mass is dissipated. How much fat will he use up considering the work done only when the weight is lifted up ? Fat supplies J of energy per kg which is converted to mechanical energy with a 20% efficiency rate. Take :
Answer: (D)
Solution
Work = 10 × 9.8 × 1 × 1000 = 9.8 × J. Useful energy per kg of fat = 0.2 × 3.8 × =
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account