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JEE Main 2016 Physics question

PhysicsRay Optics and Optical InstrumentsJEE Main 2016

In an experiment for determination of refractive index of glass of a prism by i – δ, plot, it was found that a ray incident at angle 35°, suffers a deviation of 40° and that it emerges at angle 79°. In that case which of the following is closest to the maximum possible value of the refractive index ?

Answer: (A)

Solution

A = i + e − δ = 35° + 79° − 40° = 74°. Since ≤ 40°, \fracExtra open brace or missing close brace{\sin$Missing argument for \frac\frac{A +

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Question ID VK-008875