JEE Main 2016 Chemistry question
18 g glucose () is added to 178.2 g water. The vapour pressure of water (in torr) for this aqueous solution is:
Answer: (C)
Solution
Moles: glucose 0.1, water 9.9, so = 0.99. At the boiling point = 760 torr, torr.
18 g glucose () is added to 178.2 g water. The vapour pressure of water (in torr) for this aqueous solution is:
Moles: glucose 0.1, water 9.9, so = 0.99. At the boiling point = 760 torr, torr.