JEE Main 2016 Chemistry question
Decomposition of follows a first order reaction. In fifty minutes the concentration of decreases from 0.5 to 0.125 M in one such decomposition. When the concentration of reaches 0.05 M, the rate of formation of will be :
Answer: (B)
Solution
0.5 → 0.125 M is two half-lives in 50 min, so = 25 min and k = 0.693/25 = 0.0277 . Rate of decomposition = 0.0277 ×
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