JEE Main 2016 Chemistry question

ChemistryChemical KineticsJEE Main 2016

Decomposition of follows a first order reaction. In fifty minutes the concentration of decreases from 0.5 to 0.125 M in one such decomposition. When the concentration of reaches 0.05 M, the rate of formation of will be :

Answer: (B)

Solution

0.5 → 0.125 M is two half-lives in 50 min, so = 25 min and k = 0.693/25 = 0.0277 . Rate of decomposition = 0.0277 ×

See the full step-by-step solution

Create a free account to read the complete working, and practise questions like this in a timed test.

Create a free account

Question ID VK-008886