JEE Main 2017 Mathematics question
The distance of the point (1, 3, –7) from the plane passing through the point (1, –1, –1), having normal perpendicular to both the lines and , is :
Answer: (A)
Solution
Normal = (1, −2, 3) × (2, −1, −1) = (5, 7, 3), so the plane is 5x + 7y + 3z +
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