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JEE Main 2018 Chemistry question

ChemistryThermodynamicsJEE Main 2018

At 320 K, a gas A is 20 % dissociated to A(g). The standard free energy change at 320 K and 1 atm in J mol is approximately : (R = 8.314 JK mol; ln 2 = 0.693; ln 3 = 1.098)

Answer: (D)

Solution

Moles A = 0.8, A = 0.4, total 1.2 at 1 atm: ; \ln$ 6

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Question ID VK-009160