JEE Main 2019 Physics question
An alternating voltage volt is applied to a purely resistive load of 50 Ω. The time taken for the current to rise from half of the peak value to the peak value is:
Answer: (C)
Solution
Phase changes from π/6 to π/2, i.e. Δφ = π/3 = 100π Δt ⇒ Δt = 1/300 s ≈ 3.3 ms.