JEE Main 2019 Physics question
Voltage rating of a parallel plate capacitor is 500 V. Its dielectric can withstand a maximum electric field of V/m. The plate area is m. What is the dielectric constant if the capacitance is 15 pF? (given C/Nm)
Answer: (D)
Solution
d = V/E = m; \dfrac{Cd}{ε_0A}$ =
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account